package com.tfdy.util.geo;

/**
 * @author:LuxingZhou
 * @description:
 * @date:Created in2018/6/21  10:49
 */
public class CoordinateTranUtil {

    //  由高斯投影坐标反算成经纬度
    public static double[] GaussToBL(double X, double Y)//, double *longitude, double *latitude)
    {
        int ProjNo;
        int ZoneWide; ////带宽
        double[] output = new double[2];
        double longitude1, latitude1, longitude0, X0, Y0, xval, yval;//latitude0,
        double e1, e2, f, a, ee, NN, T, C, M, D, R, u, fai, iPI;
        iPI = 0.0174532925199433; ////3.1415926535898/180.0;
        //a = 6378245.0; f = 1.0/298.3; //54年北京坐标系参数
        a = 6378140.0;
        f = 1 / 298.257; //80年西安坐标系参数
        ZoneWide = 6; ////6度带宽
        ProjNo = (int) (X / 1000000L); //查找带号
        longitude0 = (ProjNo - 1) * ZoneWide + ZoneWide / 2;
        longitude0 = longitude0 * iPI; //中央经线


        X0 = ProjNo * 1000000L + 500000L;
        Y0 = 0;
        xval = X - X0;
        yval = Y - Y0; //带内大地坐标
        e2 = 2 * f - f * f;
        e1 = (1.0 - Math.sqrt(1 - e2)) / (1.0 + Math.sqrt(1 - e2));
        ee = e2 / (1 - e2);
        M = yval;
        u = M / (a * (1 - e2 / 4 - 3 * e2 * e2 / 64 - 5 * e2 * e2 * e2 / 256));
        fai = u + (3 * e1 / 2 - 27 * e1 * e1 * e1 / 32) * Math.sin(2 * u) + (21 * e1 * e1 / 16 - 55 * e1 * e1 * e1 * e1 / 32) * Math.sin(
                4 * u)
                + (151 * e1 * e1 * e1 / 96) * Math.sin(6 * u) + (1097 * e1 * e1 * e1 * e1 / 512) * Math.sin(8 * u);
        C = ee * Math.cos(fai) * Math.cos(fai);
        T = Math.tan(fai) * Math.tan(fai);
        NN = a / Math.sqrt(1.0 - e2 * Math.sin(fai) * Math.sin(fai));
        R = a * (1 - e2) / Math.sqrt((1 - e2 * Math.sin(fai) * Math.sin(fai)) * (1 - e2 * Math.sin(fai) * Math.sin(fai)) * (1 - e2 * Math.sin
                (fai) * Math.sin(fai)));
        D = xval / NN;
        //计算经度(Longitude) 纬度(Latitude)
        longitude1 = longitude0 + (D - (1 + 2 * T + C) * D * D * D / 6 + (5 - 2 * C + 28 * T - 3 * C * C + 8 * ee + 24 * T * T) * D
                * D * D * D * D / 120) / Math.cos(fai);
        latitude1 = fai - (NN * Math.tan(fai) / R) * (D * D / 2 - (5 + 3 * T + 10 * C - 4 * C * C - 9 * ee) * D * D * D * D / 24
                + (61 + 90 * T + 298 * C + 45 * T * T - 256 * ee - 3 * C * C) * D * D * D * D * D * D / 720);
        //转换为度 DD
        output[0] = longitude1 / iPI;
        output[1] = latitude1 / iPI;
        System.out.println("X=" + output[0]);
        System.out.println("Y=" + output[1]);
        return output;
        //*longitude = longitude1 / iPI;
        //*latitude = latitude1 / iPI;
    }

    //  由经纬度反算成高斯投影坐标
    public void GaussToBLToGauss(double longitude, double latitude) {
        int ProjNo = 0;
        int ZoneWide; ////带宽
        double longitude1, latitude1, longitude0, latitude0, X0, Y0, xval, yval;
        double a, f, e2, ee, NN, T, C, A, M, iPI;
        iPI = 0.0174532925199433; ////3.1415926535898/180.0;
        ZoneWide = 6; ////6度带宽
        a = 6378245.0;
        f = 1.0 / 298.3; //54年北京坐标系参数
        ////a=6378140.0; f=1/298.257; //80年西安坐标系参数
        ProjNo = (int) (longitude / ZoneWide);
        longitude0 = ProjNo * ZoneWide + ZoneWide / 2;
        longitude0 = longitude0 * iPI;
        latitude0 = 0;
        System.out.println(latitude0);
        longitude1 = longitude * iPI; //经度转换为弧度
        latitude1 = latitude * iPI; //纬度转换为弧度
        e2 = 2 * f - f * f;
        ee = e2 * (1.0 - e2);
        NN = a / Math.sqrt(1.0 - e2 * Math.sin(latitude1) * Math.sin(latitude1));
        T = Math.tan(latitude1) * Math.tan(latitude1);
        C = ee * Math.cos(latitude1) * Math.cos(latitude1);
        A = (longitude1 - longitude0) * Math.cos(latitude1);
        M = a * ((1 - e2 / 4 - 3 * e2 * e2 / 64 - 5 * e2 * e2 * e2 / 256) * latitude1 - (3 * e2 / 8 + 3 * e2 * e2 / 32 + 45 * e2 * e2
                * e2 / 1024) * Math.sin(2 * latitude1)
                + (15 * e2 * e2 / 256 + 45 * e2 * e2 * e2 / 1024) * Math.sin(4 * latitude1) - (35 * e2 * e2 * e2 / 3072) * Math.sin(6 * latitude1));
        xval = NN * (A + (1 - T + C) * A * A * A / 6 + (5 - 18 * T + T * T + 72 * C - 58 * ee) * A * A * A * A * A / 120);
        yval = M + NN * Math.tan(latitude1) * (A * A / 2 + (5 - T + 9 * C + 4 * C * C) * A * A * A * A / 24
                + (61 - 58 * T + T * T + 600 * C - 330 * ee) * A * A * A * A * A * A / 720);
        X0 = 1000000L * (ProjNo + 1) + 500000L;
        Y0 = 0;
        xval = xval + X0;
        yval = yval + Y0;
        //*X = xval;
        //*Y = yval;
        System.out.println("x：" + xval);
        System.out.println("y：" + yval);

    }
}
